Practice Questions on Electromagnetics

Q1.

The electric field component of a time harmonic plane EM wave traveling in a nonmagnetic lossless dielectric medium has an amplitude of 1 V/m. 

If the relative permittivity of the medium is 4, the magnitude of the time-average power density vector (in W/$ \text m^2 $) is:

A.

$ \dfrac{1}{30\pi} $

B.

$ \dfrac{1}{60\pi} $

C.

$ \dfrac{1}{120\pi} $

D.

$ \dfrac{1}{240\pi} $

 View Ans

Q2.

 The inner broad-wall dimension of a rectangular waveguide having $\text{TE}_{10}$ mode as dominant mode is 2.5 cm. The cut off frequency for the mode $ \text{TE}_{30} $ is:

A.

9 GHz

B.

18 GHz

C.

22 GHz

D.

34 GHz

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Q3.

A current sheet in the +z direction, $ K=8 a_{z}\text A/\text m $ at $ x=0 $ separates region 1, $ x<0 $ where $ H_{1}=12a_{y} \text A/m $ and region 2 $ x>0 $. The value of $ H $ (in $ \text A/m $) in region 2 at $ x=+0 $.

A.

$ 8a_{y} $

B.

$ 14a_{y} $

C.

$ 16a_{x} $

D.

$ 20a_{y} $

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Q4.

The propagation constant of a lossy dielectric medium is 0.0183 rad/s and has a loss tangent 0.2. The dielectric constant of the medium 2.5. The carrier frequency of the signal propagating in this medium is:

A.

340 kHz

B.

550 kHz

C.

790 kHz

D.

1120 kHz

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Q5.

The electric field of a uniform plane wave is given by
\begin{align*}
E&=\hat {x}30\sin (3\pi 10^8-\pi z)+\hat y 30 \cos (3\pi 10^8t-\pi z)\text{ V/m}
\end{align*}
The corresponding magnetic field is:

A.

$-\hat x 0.079\cos (3\pi 10^8t-\pi z)+\hat y 0.079\sin (3\pi 10^8 t-\pi z)\text{ A/m}$

B.

$-\hat x 0.054\cos (3\pi 10^8t-\pi z)-\hat y 0.054\sin (3\pi 10^8 t-\pi z)\text{ A/m}$

C.

$-\hat x 0.079\cos (3\pi 10^8t-\pi z)+\hat y 0.054\sin (3\pi 10^8 t-\pi z)\text{ A/m}$

D.

$-\hat x 0.054\cos (3\pi 10^8t-\pi z)-\hat y 0.079\sin (3\pi 10^8 t-\pi z)\text{ A/m}$

 View Ans


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